$40 + $15g
So let’s say she has 3gb of data it would be 40+15(3)
Answer:
D. -1/8
Step-by-step explanation:
Answer:
i think it is E
Step-by-step explanation:
Answer:
The answer to this equation is 8
Step-by-step explanation:
![\frac{x}{8} +4=5\\](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D%20%2B4%3D5%5C%5C)
<u>First: Subtract</u>
![8-4=4](https://tex.z-dn.net/?f=8-4%3D4)
meaning that 5 is greater than 4.
You still need another number to make it equal than or greater than or equal to five.
![5-4=1](https://tex.z-dn.net/?f=5-4%3D1)
Since 5 minus 4 does equal 1
You need somewhere to divide it from to get 1 so you can add up the 4 to it and get the answer to the equation.
<u>Lastly: Divide</u>
![\frac{8}{8} =1](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B8%7D%20%3D1)
![1+4=5\\5=5\\4\neq 5](https://tex.z-dn.net/?f=1%2B4%3D5%5C%5C5%3D5%5C%5C4%5Cneq%205)
Now, if you do 8/8 which equals 1, 1+4 = 5; Now everything is, <u>equaled</u> up!
<u>So in conclusion...</u>
![\frac{x}{8} +4=5\\x=8\\\frac{8}{8}=1\\1+4=5\\5\neq5](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D%20%2B4%3D5%5C%5Cx%3D8%5C%5C%5Cfrac%7B8%7D%7B8%7D%3D1%5C%5C1%2B4%3D5%5C%5C5%5Cneq5)
Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.
Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21
Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5
Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.