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Paha777 [63]
3 years ago
7

On Tuesday, Allison earned $39.25 for watching the smith twins for 5 hours. How much does Allison get paid per hour to watch the

twins
Mathematics
2 answers:
Mkey [24]3 years ago
5 0
Alison earned $39.25 for watching twins for 5 hours. The question that is being asked is How much she gets paid "per hour", so what you do is divide that. 

39.25/5, which equals 7.85. 

HOPE THIS HELPED!!! =)
musickatia [10]3 years ago
3 0
I believe it's $7.85 for 1 hour. I divided $39.35 by 5.
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Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a de
Ganezh [65]

Answer:

a. \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

b. \mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

Step-by-step explanation:

The initial value problem is given as:

y' +y = 7+\delta (t-3) \\ \\ y(0)=0

Applying  laplace transformation on the expression y' +y = 7+\delta (t-3)

to get  L[{y+y'} ]= L[{7 + \delta (t-3)}]

l\{y' \} + L \{y\} = L \{7\} + L \{ \delta (t-3\} \\ \\ sY(s) -y(0) +Y(s) = \dfrac{7}{s}+ e ^{-3s} \\ \\ (s+1) Y(s) -0 = \dfrac{7}{s}+ e^{-3s} \\ \\ \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

Taking inverse of Laplace transformation

y(t) = 7 L^{-1} [ \dfrac{1}{(s+1)}] + L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{(s+1)-s}{s(s+1)}] +L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{1}{s}-\dfrac{1}{s+1}] + L^{-1}[\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{1}{s+1}] = e^{-t}  = f(t) \ then \ by \ second \ shifting \ theorem;

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{f(t-3) \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{e^{(-t-3)} \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

= e^{-t-3} \left \{ {{1 \ \ \ \ \  t>3} \atop {0 \ \ \ \ \  t

= e^{-(t-3)} u (t-3)

Recall that:

y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

Then

y(t) = 7 -7e^{-t}  +e^{-(t-3)} u (t-3)

y(t) = 7 -7e^{-t}  +e^{-t} e^{-3} u (t-3)

\mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

3 0
3 years ago
Rachel solved 50 problems of her Homework correctly and scored 62.5%. How many problems were there in the Homework?
maria [59]

Answer:

80

Step-by-step explanation:

50 problems/x total = 62.5%

50/62.5=0.8 problem for each percent

0.8 * 100 percent = 80 problems

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Read 2 more answers
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Misha Larkins [42]

Answer: t = -1

Step-by-step explanation:

8 0
3 years ago
suppose the farmer buys another 1/2 square mile of land and divides all his land into square fields 1/4 mile long and 1/4 mile w
emmasim [6.3K]
Total area of land = 1 + 1/2 = 3/2 square miles

Area of square fields = 1/4 x 1/4 = 1/16 square miles

Number of fields = (3/2) / (1/16) = 24 fields.
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3 years ago
You earn $13 for every hour that you babysit. Because you do such a fantastic job, you are also given a $20 tip at the end of th
andrezito [222]

Answer:

Step-by-step explanation:

y(h)=13h+20

7 0
3 years ago
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