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3 years ago

5

a company makes wax candles in the shape of a cyclinder. each candle has a radius of 4 inches and a height of 2 inches. how much

wax will the company need to make 160 candles

1 answer:

LenaWriter [7]3 years ago

8 0

Roughly 16084.8

If the volume is roughly 100.53, then times that by 160, then you get roughly 16084.8

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Solve for s.<br> 8 - 4s = s + 13

Andrej [43]

Answer:

s= -1

Step-by-step explanation:

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3 years ago

Cora uses 6.2 pints of white paint and blue paint to paint her bedroom walls. 2 5 of this amount is white paint, and the rest is

zhenek [66]

Answer:She used 3.72 pints of blue paints for the wall

Step-by-step explanation:

Total Quantity of Blue and white paint =6.2 pints

Quantity of White paint =2/ 5 x 6.2 pints = 2.48 pints

Quantity of blue paint =Total Quantity -Quantity of White paint

=6.2 pints-2.48 pints

=3.72 pints

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2 years ago

Explain why ΔABC cannot be shown to be congruent to ΔCDA.

igomit [66]

There isn't enough info to prove the triangles to be congruent or not. So we can't say for sure either way.

We have angle CAD = angle ACB given by the arc markings, and we know that AC = AC due to the reflexive theorem. However we are missing one third piece of information.

That third piece of info could be....

AD = BC which allows us to use SAS
angle ACD = angle CAB which allows us to use ASA
angle ABC = angle CDA which allows us to use AAS (slight variation of ASA)

Since we don't know any of those three facts, we simply don't have enough information.

side note: If AB = CD, then this leads to SSA which is not a valid congruence theorem. If we had two congruent sides, the angle must be between the two sides, which is what AD = BC allows.

4 0

3 years ago

Saj wants to go to all 19 home games at a football club.

Andreyy89

Answer:

£153

Step-by-step explanation:

If Saji bought a normal ticket for all 19 games, they would have to make 19 payments of £28. So, 28*19 would let us know that he would spend £532 in total. Then it's simply 532-379 to find the answer.

8 0

3 years ago

One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides

Elina [12.6K]

<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

The side of the square is 10 ft.
One of the vertices of an equilateral triangle is on the vertex of a square.
Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

$\mathbf{(1)} \ x^2=100+y^2$

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

$y+(10-y)=10$

Therefore, for Triangle 3, we have that by Pythagorean theorem:

$(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2$

Matching equations (1) and (2):

$2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0$

Using quadratic formula:

$y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68$

Finding x from (1):

$x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft$

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0

3 years ago

Read 2 more answers