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Sav [38]
3 years ago
8

What is the density of Olivine? Mass = 20g; Volume = 6.15 cubic cm. Round to TWO decimal places

Mathematics
1 answer:
vovangra [49]3 years ago
5 0
3.25 cubic cm per gram
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Cindy shoots a bottle rocket straight up into the air such that its height h, in feet, at time t, in seconds, is given by the fu
dezoksy [38]

Answer:

t = [0.493,4.2]

Step-by-step explanation:

The height of the rocket straight up into the air is given by :

h(t)=-16t^2+85t+5

We need to find the interval the rocket be at least 43 feet above the ground.

43\ge -16t^2+85t+5\\\\t\ge 0.493\ and\ t\le 4.82\ s

So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].

6 0
3 years ago
The question is the photo
Readme [11.4K]
For this question you can say:
5/9( °F - 32) = -10 °C
so now you should solve the equation:
5F/9 - 160/9 = -10 
⇒ 5F/9 = -10 + 160/9 ⇒ 5F/9 = -90/9 + 160/9 ⇒ 5F/9 = 70/9 ⇒ now you can multiply both sides of the equation by 9 so you will have:
5F = 70 ⇒ F = 14 ° F :)))
i hope this is helpful
have a nice day 
6 0
3 years ago
Please help me with 7 and 9. First best answer gets brainlist.
Montano1993 [528]

I honestly have no idea

7 0
3 years ago
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What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
4 years ago
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If a graph of a set has an open circle on 1/2 and an arrow pointing to the right, then which of the following numbers is in the
tester [92]
5/6 would be the best answer beside the other 2 choices that you have
6 0
4 years ago
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