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3 years ago

Which equation is represented by the graph below?

Mathematics

1 answer:

marta [7]3 years ago

3 0

Answer:

Hello,

Answer C

Step-by-step explanation:

Since ln(1)=0

if x=1 then y=4 ==> <u>y=ln(x)+4</u>

y=ln(x) is translated up for 4 units.

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A pooled variance is an estimated weighted variance made up of several different populations when the mean of each population ma

Marta_Voda [28]

Answer:

True

Step-by-step explanation:

Considering the above definition of Pooled Variance, the correct answer is TRUE.

This is because Pooled variance is used to determine the reasonable estimates of variance, where several repeated tests are expected at each value.

This helps to provide greater precision estimates of variance.

4 0

3 years ago

ANSWER QUICK!! 75 PTS!!!

iogann1982 [59]

Answer:

2) x = -2 , y = 2

3) no solution exists

Step-by-step explanation:

Solve the following system:

{-2 x - 3 y = -2

y = 2 x + 6

Hint: | Perform a substitution.

Substitute y = 2 x + 6 into the first equation:

{-2 x - 3 (2 x + 6) = -2

y = 2 x + 6

Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.

-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Isolate terms with x to the left hand side.

Add 18 to both sides:

{-8 x = 16

y = 2 x + 6

Hint: | Solve for x.

Divide both sides by -8:

{x = -2

y = 2 x + 6

Hint: | Perform a back substitution.

Substitute x = -2 into the second equation:

Answer: {x = -2 , y = 2

4 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

High of the following described the role of mathematics in science

SpyIntel [72]

Mathematics and science go hand in hand. The branches of science which include: Physics, astronomy, chemistry, biology, etc. In all these fields you will find that you will have to use the mathematical principles and formulae to solve the numerical problems. So, science needs maths but maths does not need science.

5 0

3 years ago

HELP with number 19 please

Over [174]

Answer:

Step-by-step explanation:

jx(W)

4 0

3 years ago