The answer is a because you fill in 4 where 2(x) is for the x
Answer:
50⁰
Step-by-step explanation:
Since j and k are parallel lines cut by two transversals,
2+3+5=180⁰ <em>(</em><em>Allied</em><em> </em><em>angles</em><em>)</em>
We are given 2(60⁰) and 5(70⁰)
so,
60⁰+3+70⁰=180⁰
60+70=130
130⁰+3=180⁰
Bring the 130⁰ to the R.H.S
3=180⁰-130⁰
Therefore,
3=50⁰
The Area of the platform is 33m²
Step-by-step explanation:
As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m
Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m
Since the platform is five-sided, the figure can be broken down into constituting parts
- Parallelogram ║ABCE
- Δ DCE
Are of the figure= Area of ║ABCE+ area Δ DCE
Area of ║ABCE= breadth * height
= 6*4 ⇒24m
²
Area Δ DCE= ½*(base)(height)
Putting the value of base is 6m and height as 3m
Area Δ DCE= ½*6*3
=9m
²
Total area= 24+9= 33m
²
Answer:
A)11
Step-by-step explanation:
These are matrices one dimensional with one column and 3 rows each.
-The product of the matrices is obtained by multiplying the correspond values and summing up;
![pq=\left[\begin{array}{ccc}3\\2\\-1\end{array}\right] \times\left[\begin{array}{ccc}5\\-1\\2\end{array}\right] \\\\\\\\=(3\times 5)+(2\times -1)+(-1\times 2)\\\\=15+-2+-2\\\\=11](https://tex.z-dn.net/?f=pq%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C-1%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C-1%5C%5C2%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5C%5C%3D%283%5Ctimes%205%29%2B%282%5Ctimes%20-1%29%2B%28-1%5Ctimes%202%29%5C%5C%5C%5C%3D15%2B-2%2B-2%5C%5C%5C%5C%3D11)
Hence, the product of p and q is 11
