Answer: Yes it is
Step-by-step explanation:
T1 + t2 = 2h and 30min;
t1 * 600 = t2 * 400 => t2 = (3/2) * t1;
then, t1 + (3/2) * t1 = 2h and 30min => 2t1 + 3t1 = 5h => 5*t1 = 5h => t1 = 1h => t2 = 1h and 30 min;
The distance is 2 * 1 * 600 = 1200miles;
Answer:Cross multiply and solve for x.
x/6 = 5/1.25
let the height of building be h ft
h/6 = 60/15
h = 6(60/15) = 24
the building is 24 ft high
Step-by-step explanation:
Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)
Answer:of sorry but not gunna do all that or is it just a lil bit tell me
Step-by-step explanation:
Answer:
A. 40x + 10y + 10z = $160
B. 8 Roses, 2 lilies and 2 irises
C.
1. 20x + 5y + 5z = $80
2. 4x + y + z = $16
3. 8x + 2y + 2z = $32
Step-by-step explanation:
Cost for each flower = $160/5 = $32
So we have $32 for each bouquet consisting of 12 flowers each.
Roses = x = $2.50 each
lilies = y = $4 each
irises = z = $2 each
8x + 2y + 2z = $32
8($2.50) + 2($4) + 2($2) = $32
$20 + $8 + $4 = $32
$32 = $32
a. Maximum budget is $160
40x + 10y + 10z = $160
40($2.50) + 10($4) + 10($2) = $160
$100 + $40 + $20 = $160
$160 = $160
b. From above
8x + 2y + 2z = $32
8 Roses, 2 lilies and 2 irises
c. No. There are other solutions If total cost is not limited
1. 20x + 5y + 5z
20($2.50) + 5($4) + 5($2)
$50 + $20 + $10
= $80
2. 4x + y + z
4($2.50) + $4 + $2
$10 + $4 + $2
= $16
3. 8x + 2y + 2z
8($2.50) + 2($4) + 2($2)
$20 + $8 + $4
= $32