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AveGali [126]
3 years ago
7

Which equation represents a line which is parallel to the line 4y-x=-24?

Mathematics
2 answers:
sdas [7]3 years ago
5 0
Y=1/4x+3 is the answer. I hope this helps :)
Deffense [45]3 years ago
3 0

Answer:

Y= 1/4x-3

Step-by-step explanation:

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Evaluate the quadratic function, f(x) = 3x2<br> – 4x – 9 at x = -2
nordsb [41]

Answer:

11

Step-by-step explanation:

f(x) = 3x^2 – 4x – 9

Let x = -2

f(-2) = 3 (-2)^2 -4(-2) -9

      =3(4) +8 -9

      =12 +8 -9

      20-9

       11

3 0
4 years ago
(The question is in the photo)
Naddik [55]

Answer:

6.99

Step-by-step explanation:

11.99+2.99+5.99=20.97

20.97/3=6.99

6 0
3 years ago
Read 2 more answers
(2.1) 1. Write each repeating decimal using bar<br> notation.<br> a) 0.777 77...
Anestetic [448]
0.7 (put the bar over the 7)
7 0
3 years ago
Read 2 more answers
The greatest common factor of −27x2yz5 + 15x3z3
Goryan [66]
We have that
−27x2yz5 + 15x3z3

we know that
27-------------> 3³
15-------------> 3*5
z^5-----------> z² * z³
x³------------> x² * x

substituting in the original expression<span>

−27x2yz5 + 15x3z3---------->[-3</span>³*x²*y*z³*z²]+[3*5*x²*x*z³]

[-3³*x²*y*z³*z²]+[3*5*x²*x*z³]-------> [3*x² *z³]*{[-3² *y*z²]+[5*x]}

the greatest common factor is [3*x² *z³]
8 0
3 years ago
You wish to accumulate $14,580 in 6 years. Payments are made at the end of every six-month period into an account earning 7.2% c
BlackZzzverrR [31]
Equation required for this question:

an • 1.072^n = 14,580

Where a = payment every half year and n = number of half years

There are 12 half years in 6 years.

Therefore n = 12, substitute this.

12a • 1.072^12 = 14,580

12a = 14,580 / 1.072^12

12a = 6,330~

a = 527.5 ~
7 0
4 years ago
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