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3 years ago

Please help!

Mathematics

2 answers:

levacccp [35]3 years ago

7 0

I think it’s b:g(x)=1.5x; x=0.2

Furkat [3]3 years ago

3 0

Answer:

(a) Absolute value relationship, f(-5)=6

(b) Linear relationship, g(0.2)=0.3

Step-by-step explanation:

A modulas function always represents an absolute value relationship.

A polynomial function with degree 1 is always represents a linear function.

(a)

The given function is

$f(x)=|x-3|-2$

It is a modulas function, so it represents an absolute value relationship.

Substitute x=-5 in the given function.

$f(-5)=|-5-3|-2\Rightarrow 8-2=6$

Therefore the value of function at x=-5 is 6.

(b)

The given function is

$g(x)=1.5x$

It is a linear function, so it represents a linear relationship.

Substitute x=0.2 in the given function.

$g(0.2)=1.5(0.2)=0.3$

Therefore the value of function at x=0.2 is 0.3.

(c)

The given function is

$p(x)=|7-2x|$

It is a modulas function, so it represents an absolute value relationship.

Substitute x=-3 in the given function.

$p(-3)=|7-2(-3)|\Rightarrow |7+6|=13$

Therefore the value of function at x=-3 is 13.

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Combine like terms to simplify the following polynomial.

vampirchik [111]

Answer:

5x + 15 y - 4 (option C)

Step-by-step explanation:

Solve

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Group like terms!

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#IndonesianPride - kexcvi

7 0

3 years ago

Read 2 more answers

When a force of 36 Newtons is applied to springs S1 and S2, the displacement of the springs is 6 centimeters and 9 cm, respectiv

lozanna [386]

Answer: $200 \frac{N}{m}$

Step-by-step explanation:

Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force $F$ applied to it, as long as the spring is not permanently deformed:

$F=k \Delta x$

Where:

$F=36 N$

$k$ is the elastic constant of the spring

$\Delta x$ is the displacement of the spring after applying the force

In this case we have two springs with constants $k_{1}$ and $k_{2}$ , displacement $\Delta x_{1}=6 cm \frac{1 m}{100 cm}=0.06 m$ and $\Delta x_{2}=9 cm \frac{1 m}{100 cm}=0.09 m$ , and the same force is applied to both.