Lliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint. She wants her painting to have four

Mathematics

2 answers:

Sedaia [141]3 years ago

6 0

Answer: 10

Step-by-step explanation:

Given : lliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint.

Total number of colors = 6

If order does not matter, then we use combinations.

The number of combinations of n things taken r at a time :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

If green is already selected , then the remaining number of colors to choose = 3 out of 5 ( red, yellow, purple, orange, and blue paint.)

$^5C_3=\dfrac{5!}{3!(5-3)!}\\\\=\dfrac{5\times4\times3!}{3!2!}=10$

The number of ways can she pick four colors if green must be one of them = 10.

atroni [7]3 years ago

3 0

Answer: i believe the answer is 4

Step-by-step explanation:

she can have

green red yellow purple

green yellow purple orange

green red purple orange

green red yellow orange

i couldn't see anymore combos but i could be wrong

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A 12 - ft ladder leans against the side of a house. The bottom of the ladder is 8 ft from the side of the house. How high is the

Paha777 [63]

A^2 + b^2 = c^2
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3 years ago

Read 2 more answers

Which compound most likely contains polar covalent bonds? NaCl AlF3 Br2 NF3

belka [17]

Answer: The correct answer is $NF_3$

Explanation:

In $NF_3$ molecule, there are three bond pairs and one lone pair present in the molecule. In a molecule, lone pair present on the nitrogen atom will have a dipole moment in upward direction where as total dipole moment formed by three fluorine atoms will be more in magnitude and it will be directed in downward direction which means that the net dipole moment will be in downward direction. As shown in image attached.

Hence, covalent bond present between nitrogen and fluorine will become polar in nature.

So, the correct answer is $NF_3$ .