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Molodets [167]
3 years ago
12

Lliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint. She wants her painting to have four

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

Answer:  10

Step-by-step explanation:

Given : lliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint.

Total number of colors = 6

If order does not matter, then we use combinations.

The number of combinations of n things taken r at a time :-

^nC_r=\dfrac{n!}{r!(n-r)!}

If green is already selected , then the remaining number of colors to choose  = 3 out of 5  ( red, yellow, purple, orange, and blue paint.)

^5C_3=\dfrac{5!}{3!(5-3)!}\\\\=\dfrac{5\times4\times3!}{3!2!}=10

The number of ways can she pick four colors if green must be one of them = 10.

atroni [7]3 years ago
3 0

Answer: i believe the answer is 4

Step-by-step explanation:

she can have

green red yellow purple

green yellow purple orange

green red purple orange

green red yellow orange

i couldn't see anymore combos but i could be wrong

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Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
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Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.  

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is |S| = C(40,6).

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

|E| = C(34,6)

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is  

P(E) = \frac{|E|}{|S|}

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Therefore, the probability is 0.35

Check the attached files for additionals  

8 0
3 years ago
Someone help me with this pls
sasho [114]
The answer would be 8 ^-5
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Answer:

The manager can select a team in 61425 ways.

Step-by-step explanation:

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Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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In how many ways can the manager select a team?

2 cashiers from a set of 10.

4 kitchen crews from a set of 15. So

T = C_{10,2}*C_{15,4} = \frac{10!}{2!(10-2)!}*\frac{15!}{4!(15-4)!} = 45*1365 = 61425

The manager can select a team in 61425 ways.

7 0
2 years ago
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