All categories

3 years ago

Over a 6 week period, the price of a gallon of gas increased by 18 cents.

Mathematics

1 answer:

Fiesta28 [93]3 years ago

6 0

18 divided by 6 is 3. So 3 cents/week. Hope this helps!

You might be interested in

Pythagorean theorem: Manuel purchases a rectangular picture

san4es73 [151]

Answer:

width = 15

Step-by-step explanation:

a² + b² = c² This the the formula

(PLUG IN)

8² + b² = 17²

64 + b² = 289 (subtract 64 on both sides)

b² = 225 (square root)

b = 15

Hope this helps ya!!

8 0

3 years ago

What is the answer for this one? 2x + 3 = 9. x

hoa [83]

Answer:

3/7

Step-by-step explanation:

You want to seperate the numbers from the variable.

8 0

3 years ago

Find cos θ if csc θ = 2 and θ is in quadrant II.

natita [175]

Cosecant is one of the six trigonometric identities which is equal to the reciprocal of sine function. In this case, theta is equal to sin -1 = 1/2 equal to 30 degrees. Since this is in quadrant II, the angle is 180 - 30 or 150 degrees. cos 150 is equal to -0.866 or -ssqrt 3 over 2.

5 0

3 years ago

Show that if x and y may both be written as the sum of the squares of two rational integers, then their product xy may also be w

Georgia [21]

Answer:

See proof below

Step-by-step explanation:

One way to solve this problem is to "add a zero" to complete the required squares in the expression of xy.

Let $x=m^2+n^2$ and $y=l^2+k^2$ with $m,n,l,k\in \mathbb{Z}$ . Multiplying the two equations with the distributive law and reordering the result with the commutative law, we get $xy=(m^2+n^2)(l^2+k^2)=m^2l^2+m^2k^2+n^2l^2+n^2k^2=n^2l^2+m^2k^2+m^2l^2+n^2k^2$

Now, note that $0=2lkmn-2lkmn=2nkml-2nlmk$ by the commutativity of rational integers. Add this convenient zero the the previous equation to obtain $xy=n^2l^2-2nlmk+m^2k^2+m^2l^2+2nkml+n^2k^2=(nl-mk)^2+(ml+nk)^2$ , thus xy is the sum of the squares of $nl-mk,ml+nk\in \mathbb{Z}$ .

7 0

3 years ago

What is -3×^2+1467x-86940=0 ?

frozen [14]

For this case we must solve the following quadratic equation:

$-3x ^ 2 + 1467x-86940 = 0$

If we divide both sides of the equation by 3 we have:

$-x ^ 2 + 489-28980 = 0$

The solutions will come from:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = -1\\b = 489\\c = -28980$

Substituting:

$x = \frac {-489 \pm \sqrt {(489) ^ 2-4 (-1) (- 28980)}} {2 (-1)}\\x = \frac {-489 \pm \sqrt {239121-115920}} {- 2}\\x = \frac {-489 \pm \sqrt {123201}} {- 2}\\x = \frac {-489 \pm351} {- 2}$

The roots are:

$x_ {1} = \frac {-489 + 351} {- 2} = \frac {-138} {- 2} = 69\\x_ {2} = \frac {-489-351} {- 2} = \frac {-840} {- 2} = 420$

ANswer:

$x_ {1} = 69\\x_ {2} = 420$

5 0

3 years ago