All categories

3 years ago

Given C=n+15, determine the value of C when n=4

Mathematics

2 answers:

Masja [62]3 years ago

8 0

Answer:

Step-by-step explanation:

If N=4 and the problem is C= N+15 that means you add 4 to 15 and then get 19 which will be your answer for C. You can also check this by subtracting 19-15 or 19-4!!! I hope this helps!!! Have a great day whom ever you are

puteri [66]3 years ago

6 0

Answer: c=19 and n=4

please mark as brainliest if it helped

You might be interested in

Among all pairs of numbers (x,y) such that 3x+y=15, find the pair for which the sum of squares, x^2+y^2, is minimum. Write your

Dvinal [7]

Answer:

Minimum value occurs at (x, y) = (-5,0)

Step-by-step explanation:

Given: 3x + y =15

Rewriting this equation to Slope - Intercept form, we get:

y = -3x + 15

Squaring both sides,

$y^2 = (-3x + 15)^2$

$\implies y^2 = 9x^2 - 90x + 225$

Substituting in $x^2 + y^2,$ we get:

$x^2 + 9x^2 - 90x + 225$

= $10x^2 - 90x + 225$

Comparing this equation with $ax^2 + bx + c$ we get $a =10$ and $b = - 90$ .

The minimum value occurs at the axis of symmetry given by $x = \frac{-b}{2a}$ .

Therefore, x = - $\frac{-90}{2.10}$

$\implies x = 5$

If x = 5, y = -3(5) + 15 = 0

Thus, the point becomes (5,0) where it is minimum.

5 0

4 years ago

Please help me <br><br>If 180°<α<270°, cos⁡ α=−8/17, what is sin -α?

rewona [7]

Starting from the fundamental trigonometric equation, we have

$\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}$

Since $180$ , we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

$\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}$

Plugging the numbers, we have

$\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}$

Now, just recall that

$\sin(-\alpha)=-\sin(\alpha)$

to deduce

$\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}$

6 0

3 years ago

Read 2 more answers

Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.

lakkis [162]

Answer:

Option B) 9.1

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

$=\dfrac{\sigma}{\sqrt{n}}$

Putting values, we get,

Standard error =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{63.7}{\sqrt{49}} = 9.1$

Thus, the correct answer is

Option B) 9.1

8 0

3 years ago

(x² + x - 17) ÷ (x - 4)

ludmilkaskok [199]

Answer:
(X^2 + X-17) /x-4

5 0

3 years ago

PlEASE HELP ASAP!!!! USATEST PREP DUE TODAY!!!Please No Links!!!

dedylja [7]

okey no links here u go

Answer:

Step-by-step explanation:

[4^2/(-1+3)^3+2*10] / (10+1)

= [16/8+20] / 11

= 22/11

Hope this helps :) Giving me brainiest would help a lot :))

8 0

3 years ago