2 points=2%=0.02
205000×0.02=4,100 cost of 2 points
Closing costs is
4,100+450+575+600
=5,725....answer
Hope it helps!
Complete question:
He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is
a) less than 8 minutes
b) between 8 and 9 minutes
c) less than 7.5 minutes
Answer:
a) 0.0708
b) 0.9291
c) 0.0000
Step-by-step explanation:
Given:
n = 47
u = 8.3 mins
s.d = 1.4 mins
a) Less than 8 minutes:
P(X' < 8) = P(Z< - 1.47)
Using the normal distribution table:
NORMSDIST(-1.47)
= 0.0708
b) between 8 and 9 minutes:
P(8< X' <9) =
= P(-1.47 <Z< 6.366)
= P( Z< 6.366) - P(Z< -1.47)
Using normal distribution table,
0.9999 - 0.0708
= 0.9291
c) Less than 7.5 minutes:
P(X'<7.5) =
P(X' < 7.5) = P(Z< -3.92)
NORMSDIST (-3.92)
= 0.0000
a). (20 x 80) + (20 x 6) + (7 x 80) + (7 x 6)
Answer:
(A) 40 km
(B) 90 km
(C) 180 km²
Step-by-step explanation:
To find the missing side of this triangle, let's use the Pythagorean theorem.
, assuming that a and b are legs, and c is the hypotenuse.
Assuming the 9km side is a, we need to find the value of b, so we can substitute into the equation.
So, the length of the missing side is 40. Now that we know this piece of information, we can find the perimeter and area of the triangle.
The perimeter is all the sides added together, so km is the perimeter.
The area are the two legs multiplied divided by 2.
So,
So the area of this triangle is 180 cm²
I hope this helped!
If the coefficient squared is greater than one (multiplication), it stretches the graph vertically by the factor of the coefficient.
If the coefficient squared is less than one (division), it compresses the graph vertically by the factor of the coefficient.