$\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &24000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=\textit{elapsed time}\dotfill &t\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current value}}{\stackrel{A}{\stackrel{\downarrow }{P(t)}}}=24000(1-0.08)^{\stackrel{\stackrel{\textit{years}}{\downarrow }}{t}}$

5 0

2 years ago

I need someone who will answer all five questions correctly. Give out 100 bonus points for who will answer all 5 correctly

KATRIN_1 [288]

Answer:

The circumference of the yellow circle is $9\pi$ or $28.27cm^2$ approximately, the circumference of the blue circle is $6\pi$ or $18.85m^2$ approximately, the circumference of the green circle is $80\pi$ or $251.33mm^2$ approximately, the circumference of the red circle is $5\pi$ or $15.71cm^2$ approximately, and the circumference of the pink circle is $7\pi$ or $21.99cm^2$ approximately.

Step-by-step explanation:

To find the circumference of a circle, you need to multiply the diameter of the circle and multiply it by $\pi$ . In this case, the circumferences of the yellow circle are $9\pi$ or approximately $28.27cm^2$ , the circumference of the blue circle is $6\pi$ or approximately $18.85m^2$ , the circumference of the green circle is $80\pi$ or approximately $251.33mm^2$ , the circumference of the red circle is $5\pi$ or approximately $15.71cm^2$ , and the circumference of the pink circle is $7\pi$ or approximately $21.99cm^2$ .

8 0

2 years ago

A process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of175. A ran

Tom [10]

Answer:

the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

Step-by-step explanation:

since the variance S² of the batch follows a normal distribution , then for a sample n of 20 distributions , then the random variable Z:

Z= S²*(n-1)/σ²

follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom

since

S² > 3.10 , σ²= 1.75 , n= 20

thus

Z > 33.65

then from χ² distribution tables:

P(Z > 33.65) = 0.02020

therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

8 0

3 years ago

Read 2 more answers

1 of 6

nasty-shy [4]

Answer:

something

Step-by-step explanation:

sry i need answers

3 0

2 years ago