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Kay [80]
3 years ago
14

What is d and how would I find its value

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
D-value (meteorology) in meteorology refers to the deviation of actual altitude along a constant pressure surface from the standard atmosphere altitude of that surface.
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14 news papers for $0.25
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Read 2 more answers
Geometry help plz will mark brainliest.
Alex17521 [72]
I think it's 12x.
I'm not a 100% sure though, but I hope this helps. =^D
5 0
2 years ago
If two angles of one triangle are congruent to two angles of another triangle, then the _____ are congruent.
Paraphin [41]

Answer:

TRIANGLES

Step-by-step explanation:

3 0
3 years ago
Point A is at (6,-6) and point C is at(-6,-2). find the coordinates of B on AC so that AB= 3/4AC.
loris [4]

Answer:

B(-6, 0)

Step-by-step explanation:

You want to find B such that ...

(B -A) = (3/4)(C -A) . . . . the required distance relation

4(B -A) = 3(C -A) . . . . . . multiply by 4

4B = 3C +A . . . . . . . . . . add 4A, simplify

Now, we can solve for B and substitute the given coordinates:

B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)

The coordinates of point B are (-6, 0).

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

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6 0
3 years ago
A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A
Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias  = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}

If you divide both you can get the growth rate:

\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000

7 0
3 years ago
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