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3 years ago

6

Help please!! (ill give brainliest)

1 answer:

KATRIN_1 [288]3 years ago

5 0

Pretty sure it’s 20degrees so D!!

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When artists create a three dimensional object that does not enclose all sides, we refer to it as having open volume. Group of a

Alina [70]

Answer:

True

Step-by-step explanation:

When artist encloses a space with materials that are not completely solid, it is an open volume. since the materials are not completely solid, it does not enclose all sides. Such a three dimensional object with all sides not enclosed is referred to as an open volume.

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

olga nikolaevna [1]

$f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i$

${x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4$

The Lagrangian is

$L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)$

with partial derivatives (all set equal to 0)

$L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}$

for $1\le i\le n$ , and

$L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0$

Substituting each $x_i$ into the second sum gives

$\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4$

Then we get two critical points,

$x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}$

or

$x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}$

At these points we get a value of $f(x_1,\cdots,x_n)=\pm2\sqrt n$ , i.e. a maximum value of $2\sqrt n$ and a minimum value of $-2\sqrt n$ .

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3 years ago

The graph below represents a function.

Fofino [41]

Answer:

B

Step-by-step explanation:

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3 years ago

F(x) = 7 - 5x range is

erik [133]

1.4 7/5 is 1.4 or 1 1/4

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3 years ago

Geometry HELP PLEASE and explain how I can get it

Vika [28.1K]

Please check the attached image for answer.

<em>By </em><em>Benjemin</em>

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3 years ago