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Citrus2011 [14]
3 years ago
6

What is the surface area of a sphere with a diameter of 16 cm?

Mathematics
1 answer:
Vilka [71]3 years ago
6 0

Answer:

804.25 cm² (corrected to 2 decimal places)

Step-by-step explanation:

Radius = diameter / 2

= 16/ 2

=8 cm

Surface area of sphere = 4πr²

= 4π8²

=804.25 cm² (corrected to 2 decimal places)

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7x+2z+16

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The measure of one acute angle in this right triangle is 45°.
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An electronic system has each of two different types of components in joint operation. Let X and Y denote the lengths of life, i
AURORKA [14]

Answer:

a

The average cost is E(C) = 66

b

The standard deviation of  cost is  \sigma  = 9.798

Step-by-step explanation:

From the question we are told that

          E(X) =  4

          E(Y) =  2

          E(X^2) =  24

           E(Y^2) =  8

The cost of replacing the two component is  C =  50 + 2 X + 4 Y

The variance   of X is mathematically represented as

           V(X) =  E(X^2) - [E(X)]^2

Substituting values  

              V[X] =  24 - 4^2

               V[X] =8

The variance  of Y is mathematically represented as

           V(Y) =  E(Y^2) - [E(Y)]^2

Substituting values  

              V[Y] =  8 - 2^2

               V[X] =4

The average of  replacing the two component is  

        E(C) =  2 * E(X)  + 4* E(Y)

substituting value

         E(C) =  50 + 2 * (4)  + 4* (2)

         E(C) = 66

The variance  of replacing the two component is  

        V(C) = V(50 + 2X +4Y)      Note: The variance of constant is zero

                                                                  and X and  Y are independent  

=>      V(C) =  2^2 * V(X) + 4^2 * V(Y)

substituting values

=>       V(C) =  4 * 8 +  16 * 4        

=>         V(C) =  32 + 64

=>         V(C) = 96

The standard deviation is

         \sigma  =  \sqrt{V(C)}  

substituting values

           \sigma  =  \sqrt{96}

           \sigma  = 9.798

6 0
2 years ago
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