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MaRussiya [10]
3 years ago
11

Barbara is a waitress and she usually takes between 5 and 9 tables at a time. She found that when she is assigned five tables, s

he averages $15 in tips per table per shift. If she is assigned more tables, the amount of attention she gives to each table decreases. Therefore, she averages less in tips per table. Suppose each additional table causes every table to bring in $3 less in tips. Which of the following equations could be used to find the amount of money she would make in tips if she takes 5 + x tables?
A.
T(x) = -3x2 + 75
B.
T(x) = 20 - x
C.
T(x) = x2 + 5x
D.
T(x) = 3x2 + 75
Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

A. T(x) = -3x² + 75

Step-by-step explanation:

The number of tables she takes is 5 + x.  The amount she makes from each table is 15 − 3x.  So the total is:

T(x) = (15 − 3x) (5 + x)

T(x) = 3 (5 − x) (5 + x)

T(x) = 3 (25 − x²)

T(x) = 75 − 3x²

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Colton wrote a ratio comparing the number of sports video games that he owns to the number of driving video games that he owns a
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3 years ago
Ali has x cards.
valentina_108 [34]

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

If Ali has x cards, then Belinda has 2x cards.

If Ali has x cards, then Charlie has x+5 cards.

2x (Belinda) + x+5 (Charlie) + x (Ali) = 33 (total)

2x + x+5 + x = 33

Now simplify the equation... x+x+5 can be simplified as 2x+5.

2x+5 plus 2x can become 4x+5.

So their total number is 4x+5.

So 4x+5=33.

You want to isolate the variables and numbers.

To remove the 5 from the left side, subtract 5 from both sides.

4x+5-5=4x - 33-5=28

So the equation now is 4x=28

To remove the 4, divide each side by 4.

4x÷4=x - 28÷4=7

So x equals 7, Ali has 7 cards.

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

5 0
3 years ago
Read 2 more answers
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

1000=P(1+\frac{0.06}{0.5})^{0.5*6}

1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

P\approx 712

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0
3 years ago
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