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3 years ago

Tomas bought a book that cost $18. it was on sale for 84% of its original price. how much did tomas pay

Mathematics

2 answers:

svlad2 [7]3 years ago

5 0

You said so yourself, Tomas paid $18.
The original price of the book was about $21.43.

inysia [295]3 years ago

4 0

Answer: 15.12

Step-by-step explanation:

84% of 18

=84/ 100 × 18

=84× 18 / 100

=1512/100

=15.12

The original price is $15.12

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Answer: Option (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

Explanation:

Given expression:

$(2^3)(2^{-4})$

<em>Step-1: </em>Add the exponents and keep the same base by using $x^a*x^b = x^{a+b}$ property.

$(2^3)(2^{-4}) = 2^{(3+(-4))} = 2^{-1}$

Step-2: The reciprocal of $2^{-1}$ is $\frac{1}{2^{-1}}$ , which is $2^1$

Step-3: The exponent of $2^1$ is +1; therefore, change the sign of exponent. The end expression will now become:

$2^{-1}$

Hence, the correct option is (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

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Francis is playing an online game. He has 25 points and earns 5 points for each puzzle he solves correctly. He will advance to t

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Answer:

B. 5x + 25 > 75

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It can also be written as

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5x + 25 > 75

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x > 50 / 5

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B. 5x + 25 > 75

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Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

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$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

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$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$

c) P(completing the exam in more than 90 minutes)

P(x > 90)

$P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%$

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Number of children =

$\dfrac{15.87}{100}\times 60 = 9.52\approx 10$

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