Left and right affect domain. (x)
Up and down effects range. (y)
So,
-2+5 (because the right of the number line is an increase)
7-2 (because you are decreasing by going down)
You are left with:
R'(3,5)
I hope this helps!
~cupcake
Answer:
2/3
Step-by-step explanation:
If 2/3 · x= 4/9 then 4/9 ÷ 2/3= x
KCF (Keep Change Flip)
Keep 4/9
4/9 ÷ 2/3
Change from division to multiplication
4/9 · 2/3
Flip 2/3 to 3/2
4/9 · 3/2
Multiply 4 · 3= 12
Multiply 9 · 2= 18
Simplify
12 ÷ 6= 2
18 ÷ 6= 3
x=2/3
Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and
.
To find:
The
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
![m\angle OBA=m\angle BCD](https://tex.z-dn.net/?f=m%5Cangle%20OBA%3Dm%5Cangle%20BCD)
![m\angle OBA=30^\circ](https://tex.z-dn.net/?f=m%5Cangle%20OBA%3D30%5E%5Ccirc)
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]
![m\angle OAB=m\angle OBA](https://tex.z-dn.net/?f=m%5Cangle%20OAB%3Dm%5Cangle%20OBA)
![m\angle OAB=30^\circ](https://tex.z-dn.net/?f=m%5Cangle%20OAB%3D30%5E%5Ccirc)
In triangle AOB,
![m\angle OAB+m\angle OBA+m\angle AOB=180^\circ](https://tex.z-dn.net/?f=m%5Cangle%20OAB%2Bm%5Cangle%20OBA%2Bm%5Cangle%20AOB%3D180%5E%5Ccirc)
![30^\circ+30^\circ+m\angle AOB=180^\circ](https://tex.z-dn.net/?f=30%5E%5Ccirc%2B30%5E%5Ccirc%2Bm%5Cangle%20AOB%3D180%5E%5Ccirc)
![60^\circ+m\angle AOB=180^\circ](https://tex.z-dn.net/?f=60%5E%5Ccirc%2Bm%5Cangle%20AOB%3D180%5E%5Ccirc)
![m\angle AOB=180^\circ-60^\circ](https://tex.z-dn.net/?f=m%5Cangle%20AOB%3D180%5E%5Ccirc-60%5E%5Ccirc)
![m\angle AOB=120^\circ](https://tex.z-dn.net/?f=m%5Cangle%20AOB%3D120%5E%5Ccirc)
Therefore, the measure of angle AOB is 120 degrees.
you can compare the length of sides of both the triangles...