Answer:
4.8 megabytes / minute.
Step-by-step explanation:
At the beginning of recording the download you have 24 megabytes.
15 minutes later, you have 96 megabytes.
In 15 minutes you have downloaded 96 - 24 = 72 megabytes
So the question turns out to be a proportion of
x megabytes / 1 minute = 72 megabytes / 15 minutes.
x = 72/15
x = 4.8 megabytes / minute
Answer:
x ∈ {−0.766664695962, 2, 4}
Step-by-step explanation:
The equation is a combination of polynomial and exponential functions. There are no algebraic methods for solving such an equation. Graphical and iterative methods work nicely, though.
The attached graph shows integer solutions at x=2 and x=4. There is also an irrational negative solution near x = −0.766664695962. The latter was found by using Newton's method iteration on the graphical value of -0.767.
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
I’m not gonna lie I don’t know the answer I’m just answering random questions to get points I’m so sorry
