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Harman [31]
3 years ago
6

Which quadratic equation defines the function that has zeros at -8 and 6?

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

Well, if 'y' has zeros at  x=6  and  x=-8,
then 'y' must be the product

                     y  =  (x - 6) (x + 8)

Perform the multiplication to get the quadratic function:

                     y  =  x² + 2x - 48

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Four brothers and their sister have the average age 7. Four brothers have the average age 6. How old is the sister?
AnnyKZ [126]

Answer:

11 years old

Step-by-step explanation:

If four brothers have the average age 6, then the sum of their ages is

4\cdot 6=24

years.

Let x years be the age of sister. If four brothers and their sister have the average age 7, then

\dfrac{24+x}{5}=7.

Multiply this equation by 5:

24+x=35\Rightarrow x=35-24=11.

The sister is 11 years old.

4 0
3 years ago
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jok3333 [9.3K]
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What is the arithmetic mean of the following<br> numbers?<br> 10,6, 4, 4, 6, 4, 1
slamgirl [31]

Answer:

5

Step-by-step explanation:

When you add up the values you get 35, then you divide it by the number of numbers in the set, which is 7, so when you divide 35/7, you end up with 5.

5 0
3 years ago
Can someone understand this? 2 3 and 4 plz
Sholpan [36]
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8 0
3 years ago
Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
3 years ago
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