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Andreas93 [3]
3 years ago
5

This coordinate grid shows where Alberto's school is located. Each unit represents one block. Alberto's house is at (3,4). The l

ibrary is located at the reflection of (3,4) across the y-axis.
PART A
What are the coordinates of the library?Explain how you know.

PART B
not needed
PART C
Use absolute value to find the distances from Albertos house to the school and from Albertos house to the library.

Mathematics
2 answers:
Nikitich [7]3 years ago
3 0

Answer:

Part A) -3, 4 Part C) 12 i think

Step-by-step explanation:

timurjin [86]3 years ago
3 0

Answer:

Part A-(3,4)

Part B- 2 units

Step-by-step explanation:

Part A- (x,y)--->(-x,y)

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Answer:

5 + 2.5 > 4 feets

4 + 5 > 2.5 feets

2.5 + 4 > 5 feets

Step-by-step explanation:

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Side Given are :

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In other to obey the triangle rule :

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3 years ago
What are thesolutions to the quadratic equation 0=−32−4+5?
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Answer:

-31

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5 0
4 years ago
A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr
Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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This means that \pi = 0.35

0.95 = 95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

To update this study, how many junior executives should be surveyed?

Within 3% of the proportion, which means that this is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.35*0.65}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.35*0.65}

\sqrt{n} = \frac{1.96\sqrt{0.35*0.65}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.35*0.65}}{0.03})^2

n = 971.2

Rounding up:

972 junior executives should be surveyed.

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3 years ago
B is the midpoint of AC
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It’s easier to upload the photo I think

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What percent of 44 is 33
Keith_Richards [23]
Your answer would be 133.33%

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