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labwork [276]
3 years ago
14

What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in

Mathematics
1 answer:
xeze [42]3 years ago
6 0

ANSWER

197 {in}^{2}

EXPLANATION

The area of the two tra-pezoidal faces

= 2 \times  \frac{1}{2}  \times (9 + 5) \times 5 = 70 {in}^{2}

The area of the 5 by 6.4 rectangular face

= 6.4 \times 5 = 32  {in}^{2}

The area of the two square faces

= 2(5 \times 5) = 50 {in}^{2}

The area of the 9 by 5 rectangular face is

= 9 \times 5 = 45 {in}^{2}

The surface area of the design is:

70 + 32 + 50  + 45=197 {in}^{2}

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Does anyone know how to do this?? Help please!!!!
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Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

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This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

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Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

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Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

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a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

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a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

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Answer:

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