Question

What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in

Answer 1

ANSWER

$197 {in}^{2}$

EXPLANATION

The area of the two tra-pezoidal faces

$= 2 \times \frac{1}{2} \times (9 + 5) \times 5 = 70 {in}^{2}$

The area of the 5 by 6.4 rectangular face

$= 6.4 \times 5 = 32 {in}^{2}$

The area of the two square faces

$= 2(5 \times 5) = 50 {in}^{2}$

The area of the 9 by 5 rectangular face is

$= 9 \times 5 = 45 {in}^{2}$

The surface area of the design is:

$70 + 32 + 50 + 45=197 {in}^{2}$