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Maslowich
3 years ago
12

What is the value of 12x+y(3-23)/5 when x = -5 and y = 7?

Mathematics
2 answers:
aniked [119]3 years ago
7 0

Answer: -21

Step-by-step explanation:

1. Replace the x and y with the values and solve starting in the parentheses:

12-5 + ((7*(3-23))/5)

12-5 + ((7*(-20)/5)

12-5 + (-140/5)

12-5 + (-28)

7 + (-28)

-21

Anna007 [38]3 years ago
3 0

Answer:=12x−4y

tell me if im wrong

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Write a rule to describe the transformation.
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to solve the system of equations below, Becca isolated x^2 in the firs equation and then substituted it into the second equation
bija089 [108]

The resulting equation if Becca isolated x² in the first equation and then substituted it into the second equation is (9-y²) / 25 - y²/36 = 1

<h3>Equation</h3>

x² + y² = 9

x²/25 - y²/36 = 1

From (1)

x² = 9 - y²

substitute x² = 9 - y² into (2)

x²/25 - y²/36 = 1

(9-y²) / 25 - y²/36 = 1

Therefore, the resulting equation is option C; (9-y²) / 25 - y²/36 = 1

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4 0
2 years ago
Find the missing lengths: LK=15 and KH=9, find KI and HI.
Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

base^2+perpendicular^2=hypotenuse^2

Use Pythagoras in triangle HKL

LH^2+KH^2=LK^2

(LH)^2+9^2=15^2

(LH)^2+81=225

(LH)^2=144

Taking square root on both sides.

LH=12

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

(KI)^2+15^2=(12+x)^2

(KI)^2+225=x^2+24x+144

(KI)^2=x^2+24x+144-225

(KI)^2=x^2+24x-81...(1)

Use Pythagoras theorem in ΔHKI,

(KI)^2=x^2+9^2

(KI)^2=x^2+81...(2)

From (1) and (2) we get

x^2+81=x^2+24x-81

24x=162

x=\dfrac{162}{24}=6.75

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

(KI)^2=(6.75)^2+81

(KI)^2=126.5625

Taking square root on both sides.

KI=\sqrt{126.5625}

KI=11.25

Hence, the measure of KI is 11.25 units.

3 0
3 years ago
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