Answer:
The lengths of the bases are 9 inches and 15 inches.
Step-by-step explanation:
The area of trapezoid is

Given that the height of a trapezoid is 8 in. and its area is 96 in².
Assume the bases of the trapezoid be b₁ and b₂.
Since one base of the trapezoid 6 in. longer than the other.
Let, b₁=b₂+6
The area of the trapezoid is
in²
in²
in²
According to the problem,

[ Multiplying
]





Then, 
=9+6
=15 in
The lengths of the bases are 9 inches and 15 inches.
The volume of a cylinder is given by πr²h where, r is the radius of the cylinder and <span>h </span>is the height of the cylinder.
Also<span> r=d/2</span> , where d is the diameter of the cylinder.
Therefore if the diameter is halved, the radius also gets halved ,i.e., it becomes r/2. Therefore the new volume =<span> π(r/2)²h</span>
=π(r²/4)h
<span>=(1/4) πr²h</span>
<span>
</span>
Answer: C log 16
Step-by-step explanation:
Answer:
x=29
Step-by-step explanation:
3x=x+58
2x=58
x=29
Remember, SF= new/old. On shape 2, the side with the length 3 corresponds to the length of 9 on shape 1. (SF=3/9)=0.3333333....