All categories

3 years ago

Given parallel lines cut by transversal, corresponding angles are?

Mathematics

1 answer:

WITCHER [35]3 years ago

6 0

Answer:

congruent

Step-by-step explanation:

Given parallel lines cut by transversal, corresponding angles are congruent.

You might be interested in

Complete the statement.

GenaCL600 [577]

Answer:

alternate interior angles are always congruent.

Step-by-step explanation:

- Consecutive [Same-side] exterior angles are always supplementary.

- Consecutive [Same-side] interior angles are always supplementary.

- Corresponding angles are always congruent.

I am joyous to assist you anytime.

4 0

2 years ago

ABCD is a rectangle. What is the value of x? rectangle with length 63 m, width x m, and diagonal 65 m 2 meters 16 meters 63 mete

lesya [120]

The correct answer is 16 meters

Hope this helped :)

4 0

3 years ago

Read 2 more answers

Hi can someone help me out with this problem.

elena-s [515]

Answer:

third side = 9

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let the third side be x, then

x² + 40² = 41², that is

x² + 1600 = 1681 ( subtract 1600 from both sides )

x² = 81 ( take the square root of both sides )

x = $\sqrt{81}$ = 9

The third side is 9

3 0

2 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago

Find the sum of the following infinite geometric series, if it exists. 4+3.2+2.56+2.048+...

mel-nik [20]

14.848 might be not sure

3 0

3 years ago

Read 2 more answers