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maxonik [38]
3 years ago
11

Enter the equation in standard form. y = 5x - 1

Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

-5x + 1y = -1

Step-by-step explanation:

move the 5x to the other side of the equal sign.

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How do you find the rate of change for tables? For example (see photo above)
pantera1 [17]
Divide change in the output value by the change in the input value for example in this question the rate on the y=+5 and on the x value it’s +1
6 0
3 years ago
∠A and \angle B∠B are vertical angles. If m\angle A=(3x-30)^{\circ}∠A=(3x−30)
Yuki888 [10]

Answer:

x=21\textdegree

Step-by-step explanation:

So we know that:

\angle A=3x-30 \text{ and}\\\angle B=2x-9

And that the two angles are vertical angles.

Since they are vertical angles, their measurements are equivalent. Thus, to find x, set the equations equal to each other:

\angle A=\angle B\\(3x-30)=(2x-9)

Now, solve for x. Add 30 to both sides. The left side cancels:

(3x-30)+30=(2x-9)+30\\3x=2x+21

Now, subtract 2x from both sides. The right cancels:

(3x)-2x=(2x+21)-2x\\x=21

Thus, the value of x is 21.

8 0
4 years ago
The product of a linear monomial and a linear binomial is a ​
oksian1 [2.3K]

Answer:

The product of a linear monomial and a linear binomial is a second degree binomial

Step-by-step explanation:

Examples of linear monomials are:

2x

2a

y

Examples of linear binomials are:

2x+y

x-y

3a+b

x+1

When we take the product of a linear monomial and a linear bbinomial we obtain:

2a(3a+b)=6a²+2ab

y(x+1)=xy+y

y(x-y)=xy-y²

These are all second degree binomials.

4 0
4 years ago
Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
kompoz [17]
Answer:

Magnitude: 121.35 pounds

Direction: 21.64°

Explanation:

1) Decompose each force into its x - y components.

2) Force 1, F1: 140 pounds at angle of 30°

x-component: F1,x

F1, x = F1 *cos(30°) = 140 pounds * cos(30°) = 121.24 pounds

y-component: F1,y

F1,y = F1 * sin(30°) = 140 pounds * sin(30°) = 70 pounds.

3) Force 2, F2: 75 poounds at 150°

x-component: F2,x

F2,x = F2 * cos(150°) = 75 pounds * cos(150°) = - 64.95 pounds

y-component: F2,y

F2,y = F2 * sin(150°) = 75 pounds * sin(150°) = 37.5 pounds

4) Resultant Force, Fr

x-component: Fr,x

Fr,x = F1,x + F2,x = 121.24 pounds - 64.95 pounds = 56.29 pounds

y-component: Fr,y

Fr,y = F1,y + F2,y = 70 pounds + 37.5 pounds = 107.5 pounds

4.1) magnitude

|Fr| = √ [ (56.29 pouns)^2 + (107.5 pounds)^2 ] = 121.35 pounds.

4.2) direction

tan(α) = Fr,y / Fr,3 = 56.29 pounds / 107.5 pouns = 0.5236

=> α = arctan(0.5236) = 27.64 °


5 0
4 years ago
What expression represents the volume of the prism, in
valkas [14]

Step-by-step explanation:

<u>Volume of a triangular prism = 1/2 × lbh</u>

<u>Volume of a triangular prism = 1/2 × lbhSo, from given options, we can select 39 x 2 = 13 × 3 × 2 as the expression that represents the volume of the prism, with 13 as the height or length of the prism.</u>

6 0
2 years ago
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