Question

Please help me! I will mark brainliest! I don't get polynomials and all that other stuff. So this question is really hard.

Answer 1

$\bf (x-4)(x^2-5x-6) \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} (x)(x^2-5x-6)\implies &x^3-5x^2-6x\\\\ (-4)(x^2-5x-6)\implies &-4x^2+20x+24 \end{cases} \\\\\\ x^3-5x^2-6x-4x^2+20x+24\implies x^3-5x^2-4x^2-6x+20x+24 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{adding like-terms}}{x^3-9x^2+14x+24}~\hfill$

so, notice, to multiply a binomial and a trinomial, simply multiply each term of either one by one.

(a+b)(c+d+e)

a(c+d+e)

+b(c+d+e)

and then combine them and add any like terms.

Answer 2

Answer:

Using sum and product method you can simplify the top as:

x^2-4x-5 = (x-5)(x+1) and x^2-5x+4 = (x-4)(x-1)

The x-4 and the x+1 cancel each other out and you will be left with

(x-5)/(x-1)

Step-by-step explanation: