Please help me! I will mark brainliest! I don't get polynomials and all that other stuff. So this question is really hard.
2 answers:
![\bf (x-4)(x^2-5x-6) \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} (x)(x^2-5x-6)\implies &x^3-5x^2-6x\\\\ (-4)(x^2-5x-6)\implies &-4x^2+20x+24 \end{cases} \\\\\\ x^3-5x^2-6x-4x^2+20x+24\implies x^3-5x^2-4x^2-6x+20x+24 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{adding like-terms}}{x^3-9x^2+14x+24}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%28x-4%29%28x%5E2-5x-6%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20%28x%29%28x%5E2-5x-6%29%5Cimplies%20%26x%5E3-5x%5E2-6x%5C%5C%5C%5C%20%28-4%29%28x%5E2-5x-6%29%5Cimplies%20%26-4x%5E2%2B20x%2B24%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20x%5E3-5x%5E2-6x-4x%5E2%2B20x%2B24%5Cimplies%20x%5E3-5x%5E2-4x%5E2-6x%2B20x%2B24%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Badding%20like-terms%7D%7D%7Bx%5E3-9x%5E2%2B14x%2B24%7D~%5Chfill)
so, notice, to multiply a binomial and a trinomial, simply multiply each term of either one by one.
(a+b)(c+d+e)
a(c+d+e)
+b(c+d+e)
and then combine them and add any like terms.
Answer:
Using sum and product method you can simplify the top as:
x^2-4x-5 = (x-5)(x+1) and x^2-5x+4 = (x-4)(x-1)
The x-4 and the x+1 cancel each other out and you will be left with
(x-5)/(x-1)
Step-by-step explanation:
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