Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
---
Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
Answer:
(
5.5
,
4
)
Step-by-step explanation:
Use mid point formula shown in image
first x= (X+X)/2
x=(4+7)/2
x=11/2
x=5.5
y=(Y+Y)/2
y=(2+6)/2
y=8/2
y=4
(5.5,4)
The question is kind of vague in my opinion.
the best measurement to report with the scale in my opinion would be tens of pounds. my reasoning is because the decimal place would still prove importance with numbers under one hundred. above one hundred pounds and the decimal place becomes kind of pointless.
I hope I answered your question. though i'm sorry if i didn't
2x + -11 = k
Reorder the terms:
-11 + 2x = k
Solving
-11 + 2x = k
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 11 + 2x = 11 + k
Combine like terms: -11 + 11 = 0
0 + 2x = 11 + k
2x = 11 + k
Divide each side by '2'.
x = 5.5 + 0.5k
Simplifying
23% is the answer my dude
