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Gennadij [26K]
3 years ago
14

What is the length of the altitude of the equilateral triangle below? Thank you! <3

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0

<u>Answer:</u>

The correct answer option is C. 4\sqrt{3}.

<u>Step-by-step explanation:</u>

We are given an equilateral triangle which is divided into two equal halves and that makes two right angled triangles with known measures of angles.

We are to find the length of the altitude of the triangle. For that we can use the trigonometric ratios.

sin 60 = \frac{a}{8}

\frac{\sqrt{3} }{2} =\frac{a}{8}

a= \frac{\sqrt{3} }{2} \times 8

a = 4\sqrt{3}

Therefore, the correct answer option is C. 4\sqrt{3}.

irga5000 [103]3 years ago
5 0

Answer:

The correct answer option is C. . \

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  • The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is <u>translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis</u>.

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By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.

You can check that analitically

Departing from the triangle: XYZ

  • <u>Translation 5 units to the left</u>: (x,y) → (x - 5, y)

  • Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)
  • Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)
  • Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)

  • <u>Translation 1 unit down</u>: (x,y) → (x, y-1)

  • (-11,2) → (-11, 2 - 1) = (-11, 1)
  • (-9,7) → (-9, 7 - 1) = (-9, 6)
  • (-7, 2) → (-7, 2 - 1) = (-7, 1)

  • <u>Reflextion accross the x-axis</u>: (x,y) → (x, -y)

  • (-11, 1) → (-11, -1), which are the coordinates of vertex X"
  • (-9, 6) → (-9, -6), which are the coordinates of vertex Y""
  • (-7, 1) → (-7, -1), which are the coordinates of vertex Z"

Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

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