Answer:
8 5/12 > 8 3/8
Step-by-step explanation:
The integer parts of the numbers are the same, so we can find the desired result by comparing the fractions. To do that, we can subtract one from the other, or we can simply write them both with a common denominator.
<u>Subtracting</u>:
5/12 -3/8 = (5·8 -12·3)/(12·8) = 4/(12·8) = 1/24 > 0
so we have ...
5/12 > 3/8
8 5/12 > 8 3/8
__
<u>Common Denominator</u>:
The denominators of the fractions are 12 and 8. The least common multiple of these numbers is 12·2 = 8·3 = 24. Then the numbers can be written as ...
8 5/12 = 8 10/24
8 3/8 = 8 9/24 . . . . . . this is less than 8 10/24
Then the appropriate relation between the numbers is ...
8 5/12 > 8 3/8
Step-by-step explanation:
<u>Given</u><u> </u><u>that</u><u>:</u><u>-</u>
- Side AC measures 6 units
- Side BC measures 9.5 units
- Side AB measures 11 units
<u>To</u><u> </u><u>find</u><u>:</u><u>-</u>
- The cosB as a decimal rounded to the nearest hundredth
<u>We</u><u> </u><u>know</u><u> </u><u>that</u><u>, </u>

<u>Solution</u><u>:</u>





<u>Therefore:</u>
Answer:
1.033
Step-by-step explanation:
Self explanatory. It can be done with any form of division
Please mark brainliest :)
Answer:

Step-by-step explanation:
Given that:
The number of observations is:
6, 10, 12
If we are to use a simple random sampling without replacement, then we will have:
(6,10) (6,12) (10,12)
Here;
the sample size n = 2
The population size N = 3
For (6,10) ; The sample mean = 
= 
= 8
For (6,12) ; The sample mean = 
= 
= 9
For (10, 12) ; The sample mean = 
= 
= 11
The probability distribution of sample mean(x) is:
X 8 9 11
P(X=x)

Thus, the probability that the sample mean is larger than 8 is:
P(X> 8) = P(X = 9) + P(X + 11)
P(X> 8) = 
P(X > 8) = 
P(X> 8) = 