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2 years ago

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Hi so here is my quiestion in which number dose the 5 represent a value 10 times the value represented by the 5 in 35,187 so any

one smart enough to solve

1 answer:

rosijanka [135]2 years ago

7 0

Answer:

Step-by-step explanation:

The wording is a bit wonky, but

The value of the 5 in 35187 is 5000

Ten times that value is 10(5000)=50000

So in the number 50000, the 5 represents 10 times the value of 5 in 35187.

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What is the quotient?<br><br><br><br><br><br> 9

const2013 [10]

Answer:

Step-by-step explanation:

Dividing one number by another yields a quotient. The quotient of 9 divided by 15 can be expressed as a decimal or a fraction. Any time you divide a number by a larger number, the answer will always be less than one.

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2 years ago

Equation to find three consecutive odd integers whose sum is 3

KiRa [710]

The equation computed shows that the numbers will be 9, 11 and 13.

<h3>How to illustrate the information?</h3>

Let the numbers be:

First number = x

Second number = x + 2,

Third number = x + 4.

Total of the numbers = 33

The equation will be:

= first + second + third number

x + x + 2 + x + 4 = 33

3x + 6 = 33

Collect like terms

3x = 33 - 6

3x = 27.

Divide both side by 3

3x/3 = 27/3

x = 9

First number = x = 9

Second number = x + 2 = 9 + 2 = 11

Third number = x + 4. = 9 + 4 = 13

The numbers will be 9, 11, and 13.

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Illustrate the equation to find three consecutive odd integers whose sum is 33.

8 0

1 year ago

List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct

zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$

Where:

$\bar x$ = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

$\bar x$ = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

$C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }$

$\sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{0.872}}$

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0

3 years ago

Evaluate the expression when a= 4, b= - 2, and c= 7 - -> 5a - 9 (b - c)

ollegr [7]

Answer:

$65$

Step-by-step explanation:

Given the following question:

$5a-9(b-c)$
a = 4
b = 2
c = 7

In order to find the answer, we need to substitute the variables with the numbers given, and then solve using PEMDAS.

$5\times4-9\times(2-7)$
$2-7=-5$
$5\times4-9\times-5$
$5\times4=20$
$20-9\times-5$
$9\times-5=-45$
$20--45$
$20+45=65$
$=65$

Hope this helps.

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2 years ago

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8090 [49]

I need more info to answer this question

4 0

2 years ago

Read 2 more answers