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Usimov [2.4K]
3 years ago
14

Identify the function that models ignoring air resistance a ball being thrown in the air with an initial velocity of 70 ft/s fro

m a height of 5 feet
Biology
2 answers:
kenny6666 [7]3 years ago
6 0

Answer:

The required function is h(t)=-16t^2+70t+5.

Explanation:

It is given that the ball being thrown in the air with an initial velocity of 70 ft/s and from a height of 5 feet. It means

Initial velocity = 70 ft/s

Initial height = 5 feet

The general function that approximate the height  in feet of a projectile on the earth after time t is

h(t)=-16t^2+v_0t+h_0             .... (1)

Where, v₀ is initial velocity and h₀ is initial height.

Substitute v_0=70 and h_0=5 in equation (1).

h(t)=-16t^2+70t+5

Therefore, the required function is h(t)=-16t^2+70t+5.

spin [16.1K]3 years ago
5 0
Ignoring air resistance means putting variables in a controlled set-up where air is not present. This is known as a vacuum in Science. Regardless if the ball had initial velocity of 70 ft/s from a height of 5 feet, its kinetic energy as it falls to ground would be constant. This is known as the Earth's Gravity and Newton measured this that all objects fall at a rate of 9 meter per second squared. 
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Answer:

  • the allelic frequency for p is 0.967
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Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the exposed example,

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We know that 1 in 15 individuals are heterozygous, and we also know that there are no recessive homozygous, q², because they can not survive, so of the 15 individuals only one is heterozygous and the rest 14 individuals must be dominant homozygous, p².

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p²= 0.933

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So now we know that the allelic frequency for p is 0.967  

This means that the allelic frequency for q or p is 0.033, which we deduce by clearing the equation p + q = 1

                          0.967 + q = 1

                         q = 1 - 0.967

                          q = 0.033

  • the allelic frequency for p is 0.967
  • the allelic frequency for q is 0.033
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