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lyudmila [28]
4 years ago
8

What is the y-intercept of this function? f(x) = 2(x - 7)2 – 32

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
4 0

We are given the following function and want to find the y-intercept:

f(x)=2(x-7)^2-32

Just substitute the value x=0 into the equation to find the value of the y-intercept:

y=2(0-7)^2-32

Simplify

=2(49)-32

Simplify again

=66

Since the value of f(x), or y, when x=0 is 66, the y-intercept of this function is 66.

Let me know if you need any clarifications, thanks!

~ Padoru

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Answer:

  an = -39 -100(n -1)

Step-by-step explanation:

The given sequence can be described by a 3rd degree polynomial.* However, we suspect a typo, and that your intention is to have a formula for the arithmetic sequence ...

  -39, -139, -239, -339

This has a first term a1 = -39, and a common difference d = -100.

The model for the explicit formula is ...

  an = a1 +d(n -1)

Filling in the given values, the formula you seek is ...

  an = -39 -100(n -1)

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* That polynomial is ...

  an = 50n^3 +350n^2 -800n +461

This gives a sequence that starts ...

  -39, -139, -139, -339, -1039, -2539, -5139, -9139, ...

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The cost of carpeting the floor of a room, whose breadth is twice it’s height and length is twice it’s breadth, at the rate of R
Leno4ka [110]

Answer:

The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4

Step-by-step explanation:

Given as :

The cost of carpeting a room = Rs 64,000

The rate of carpeting = Rs 540 m²

The breadth is twice its height

The length is twice its breadth

Let The length = L m

The breadth = B m

The height = L m

So, according to question

L = 2 B        and    B = 2 H

Now, Area of rectangular carpet = Length × Breadth

Or,  A = L × B

Or, A = 2 B × B

∵ The cost of carpeting at the rate of Rs 540 per m² = Rs 64,000

So, area  = \frac{64000}{540}

Or, 2× B² = 118.518

Or,      B² = \frac{118.518}{2}

Or,      B² = 59.259

I,.e      B  = \sqrt{59.259} = 7.69 m

The length = 2 B

I.e   L = 2 × 7.69 = 15.38 m

and  H = \frac{B}{2}

I.e    H =  \frac{7.69}{2} = 3.84 m

So, Length = 15.38 m   ,  Breadth = 7.69 m   , height = 3.84 m

∵ The area of four wall = 2× ( Length + Breadth ) × height

or, The area of four wall = 2× ( 15.38 + 7.69 ) × 3.84

Or, The area of four wall = 177.17 m²

Now The rate of plastering the four wall = Rs 20 per square meter

So, The cost of plastering the four wall = area of four wall × rs 20

∴  The cost of plastering the four wall = 177.17 × Rs 20

I.e   The cost of plastering the four wall = Rs 3,543.4

Hence The cost of plastering the four wall at the rate of Rs 20 per meter square is Rs 3,543.4   answer

7 0
3 years ago
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