What is the equation of a line passing through (-6,5) and having a slope of 1/3 (1 over 3) ?

Mathematics

2 answers:

krek1111 [17]3 years ago

7 0

The answer is y=(1/3)x+7, use y=mx+b and solve for b where m is slope

Nikitich [7]3 years ago

3 0

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\qquad 
\qquad \qquad 
slope = m \implies \cfrac{1}{3}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=\cfrac{1}{3}[x-(-6)]\implies y-5=\cfrac{1}{3}(x+6)
\\\\\\
y-5=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+7$

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