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slavikrds [6]
3 years ago
14

For which function does f decrease by 15% every time x increases by 1

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0

Answer:

f(x) = 0.85^{x}

Step-by-step explanation:

The exponential function that decrease by 15% every time x increases by 1 is given by:

f(x) =  {(1 - 0.15)}^{x}

We simplify the parenthesis to get:

f(x) = 0.85^{x}

Therefore the decrease by 15% every time x increases by 1 is

f(x) =  {0.85}^{x}

The second choice is correct.

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Answer: The answer would be 8.

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Diamond deposited $300 in a savings account that has a 2% interest rate per
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After 1 year: $306

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x(-10.5,0)

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Inessa ran 3 laps in 8 minutes. How long would it take her to run 10 laps at this pace? (This is proportions)
Degger [83]

Answer:

26.6 minutes

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5 0
3 years ago
For his phone service, Charlie pays a monthly fee of $ 18 , and he pays an additional $ 0.06 per minute of use. The least he has
schepotkina [342]

Answer:

Charlie has used his phone in a month for at least 1404 minutes

Step-by-step explanation:

In order to solve this problem, we must first determine what will our variable be and what it will represent.

Let's say our variable is x and it will represent the number of minutes Charlie has used his phone.

After we set our variable up, we can set our equation up. The problem states that Charlie will pay a monthly fee of $18 and additional $0.06 per minute of use. The $18 is what is called a fixed cost and the $0.06 is the variable cost, which will depend on our variable x (the number of minutes spent). Taking this into account we can build an inequality that will represent the amount of money spent in a month, which will look like this:

18+0.06x\geq 102.24

so now we can solve that inequality for x, we can start by subtracting 18 from both sides, so we get.

18+0.06x-18\geq 102.24-18\\\\0.06x\geq 84.24

Next, we can divide both sides of the inequality by 0.06 so we get:

0.06x/0.06\geq 84.24/0.06\\\\x\geq 1404

so that's where the answer came from. Charly has used an amount of at least 1404 minutes

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