Answer:
The Answer is: y = -1/4x + 6
Step-by-step explanation:
Given point: (4, 5)
Given equation: y = -1/4x - 11
Slope: m = -1/4, a parallel line will have the same slope.
Start with the point slope form and solve for y:
y - y1 = m(x - x1)
y - 5 = -1/4(x - 4)
y - 5 = -1/4x + 1
y = -1/4x + 1 + 5
y = -1/4x + 6
Proof:
f(x) = -1/4x + 6
f(4) = -1/4(4) + 6
= -1 + 6 = 5, giving (4, 5)
Hope this helps!! Have an Awesome day!!! :-)
Answer:
The carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Step-by-step explanation:
Given:
Amount a carpenter can spend at most = $250
The inequality to represent the amount he can spend on each type of board is given as:
where 
represents '2 by 8 boards' and 
represents '4 by 4 boards'.
To determine whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Solution :
In order to check whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards' , we need to plugin the 
and 
in the given inequality and see if it satisfies the condition or not or in other words (12,14) must be a solution for the inequality.
Plugging in and in the given inequality
The above statement can never be true and hence the carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Answer:
-0.4 = −2/5
Step-by-step explanation:
Rewrite the decimal number as a fraction.
-0.4/1
Multiply to remove 1 decimal places.
-0.4/1 x 10/10 =4/10
Find the GCF.
4 ÷ 2/10 ÷ 2 = 2/5
x = 2/5
-2/5
Answer:
There are a few solutions because there are some fractions and decimals between 8 and 10
Step-by-step explanation:
Let the unknown number be 'x'
If the number is greater than 8 and the same number is less than 10, this can be expressed as;
x>8 and x < 10
Note that if x>8, then 8<x
The resulting inequalities are now;
8<x and x<10
Combining both inequalities we have: 8<x<10
Since the inequality didn't tell us that the variable 'x' is equal to 8 and 10, this means that our solution falls between 8 and 10 and the value of integer that falls within this range is 9. Other values that falls within this range are decimals and fractions.
Therefore it can be concluded that there are a few solutions because there are some fractions and decimals between 8 and 10
