Answer:
x= 1/2 and -3/4
Step-by-step explanation:
By using factorization, we can solve this equation.
8x^2+2x-3=0
Factor:
(2x-1)(4x+3)=0
Solve:
2x-1=0
2x=1
x=1/2
Solve again:
4x+3=0
4x=-3
x=-3/4
Hope this helped
E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15
Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.
P(F|E)=P(E and F)÷P(E)
It is given that P(E)=0.3,P(F|E)=0.5
Using Bayes' formula,
P(F|E)=P(E and F)÷P(E)
Rearranging the formula,
⇒P(E and F)=P(F|E)×P(E)
Substituting the given values in the formula, we get
⇒P(E and F)=0.5×0.3
⇒P(E and F)=0.15
∴The correct answer is 0.15.
If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.
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I think #1 is -1/2 but im not sure i dont know about the other answers
Answer:
The number of liters of 25% acid solution = x = 160 liters
The number of liters of 40% acid solution = y = 80 liters
Step-by-step explanation:
Let us represent:
The number of liters of 25% acid solution = x
The number of liters of 40% acid solution = y
Our system of Equations =
x + y = 240 liters....... Equation 1
x = 240 - y
A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution.
25% × x + 40% × y = 240 liters × 30%
0.25x+ 0.4y = 72...... Equation 2
We substitute 240 - y for x in Equation 2
0.25(240 - y)+ 0.4y = 72
60 - 0.25y + 0.4y = 72
Collect like terms
- 0.25y + 0.4y = 72 - 60
0.15y = 12
y = 12/0.15
y = 80 Liters
Solving for x
x = 240 - y
x = 240 liters - 80 Liters
x = 160 liters
Therefore,
The number of liters of 25% acid solution = x = 160 liters
The number of liters of 40% acid solution = y = 80 liters
The difference is 
.
Step-by-step explanation:
Step 1:
The polynomial 
is subtracted from the polynomial 
.
If we write this as an equation, we get
.
To subtract the polynomials, we group up the terms based on their variables.
In this subtraction, there are two variables i.e. 
and 
and there is one constant term.
Step 2:
The subtraction of the variables; 
.
The subtraction of the variables; 
.
The subtraction of the constants; 
.
So 
.
