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Montano1993 [528]
3 years ago
10

The mean high temperature on a particular day in January is 31 degrees F and the standard deviation is 8.7 degrees. One year, th

e temperature was 52 degrees F on that day. What is the Z-score for that day's temperature? Round to the appropriate number of decimal places for Z-scores. Is this temperature significantly high? (greater than 2)​
Mathematics
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

subject?

Step-by-step explanation:

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HELP ME TVT I beg you (answer by yes or no)
aliya0001 [1]

Answer:

1:yes 2:no 3:no 4:yes

Step-by-step explanation:

3*2=6 for the numerators

4*5=20 for the denominators

you can simplify this to make it 3/10 ✔️

2*5-10 for the numerators

6*5=30 for the denominators

you can simplify this to make it 1/3 ❌

1*1=1 for the numerators

10*5 for the denominators

you can turn this into 1/50 ❌

1*3=3 for the numerators

2*5=10 for the denominators

you can turn this into 3/10 ✔️

hope this helps! have a nice day! :)

5 0
2 years ago
A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a. <br> Pls
ZanzabumX [31]

Answer:

It passes through the point (3,4). Given that the center of the circle is the point (0,0). We know that the equation of the circle is given by : (x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.

6 0
3 years ago
Read 2 more answers
Given the data shown below, which of the following is the best approximation of the coefficient of determination (r^2)
HACTEHA [7]

The coefficient of determination can be found using the following formula:

r^2=\mleft(\frac{n(\sum ^{}_{}xy)-(\sum ^{}_{}x)(\sum ^{}_{}y)}{\sqrt[]{(n\sum ^{}_{}x^2-(\sum ^{}_{}x)^2)(n\sum ^{}_{}y^2-(\sum ^{}_{}y)^2}^{}}\mright)^2

Using a Statistics calculator or an online tool to work with the data we were given, we get

So the best aproximation of r² is 0.861

8 0
1 year ago
Find the equation in standard form of the line passing through the points (2,-3) and (4,2)
mario62 [17]
The line passes through (2,-3) and (4,2).

Calculate the slope of the line.
m = (2+3)/(4-2) = 5/2

The equation of the line is therefore
\frac{y-2}{x-4} = \frac{5}{2}

Cross multiply.
2(y-2) = 5(x-4)
2y - 4 = 5x - 20
2y = 5x - 16
Rewrite as
5x - 2y = 16

Answer: C. 5x - 2y = 16

8 0
3 years ago
Hi, I need to send you a screenshot​
Kazeer [188]
Whyyy notttt I guessss
6 0
3 years ago
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