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Montano1993 [528]
2 years ago
10

The mean high temperature on a particular day in January is 31 degrees F and the standard deviation is 8.7 degrees. One year, th

e temperature was 52 degrees F on that day. What is the Z-score for that day's temperature? Round to the appropriate number of decimal places for Z-scores. Is this temperature significantly high? (greater than 2)​
Mathematics
1 answer:
geniusboy [140]2 years ago
5 0

Answer:

subject?

Step-by-step explanation:

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Some carpet cleaning costs are 1 room for $125, 2 rooms for $175, 3 rooms for $225. and 4 rooms for $275.00.Find and interpret t
Free_Kalibri [48]
First calculate the hourly rate, which is the difference of cleaning 2 and 1 rooms:
175-125=50

then calculate the initial value by subtracting the hourly rate from the "1 room" cost:
125-50=75

The initial cost might be something like driving to the place (which is only necessary once), while the rate covers work time or cleaning utensils used.
8 0
3 years ago
7x+27x+2 from -5x^2-2x<br> ADDING AND SUBTRACTING POLYNOMIALS
maksim [4K]

Answer:

7x+27x=34x

34x+2-(-5×^2)-2x

34x+2+5x^2-2x

34x+2x=36x

36x+2+5x^2

6 0
2 years ago
Explain why the exponents cannot be added in the product 12 to the power of three times 11 to the power of 3
egoroff_w [7]
Normally, we could add exponents.
however, that only is possible when the bases are the same
recall what exponents mean

12³=12*12*12


so we cannot add exponents for 12³*11³ because that means 12*12*12*11*11*11
it would not equal 12⁶ or 11⁶



or you  could refer to the rule
(x^a)(x^b)=x^{a+b}
notice when x=x then we can add the bases


fun fact below
we can reverse a previous exponential rule like this
since (ab)^c=(a^c)(b^c) then (a^c)(b^c)=(ab)^c
therefor
12^3*11^3=(12*11)^3



we can't add the exponents because the bases are not the same
5 0
3 years ago
For the equation |ax+b|=c (where a,b, and c are real numbers and a≠0), what value of c results in exactly one solution?
Degger [83]

Step-by-step explanation:

Correct option is

D

a



=0,b



=0

The condition for ax+by+c=0 to be a linear eqaution in two variables is

a



=0,b



=0

7 0
2 years ago
One of the solutions to x2 − 2x − 15 = 0 is x = −3. What is the other solution?
Alex_Xolod [135]
If you factor the equation you can see what the solutions are.  Two factor a quadratic of the form ax^2+bx+c, find two values which satisfy two conditions...

jk=ac=-15 and j+k=b=-2 so j and k must be -5 and 3 so the factors are:

(x-5)(x+3)

So the other solution is x=5
7 0
2 years ago
Read 2 more answers
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