<span>5 n C r 3 = 10 </span><span>がんばってね</span>
Answer:
The third score must be larger than or equal to 72, and smaller than or equal 87
Step-by-step explanation:
Let's name "x" the third quiz score for which we need to find the values to get the desired average.
Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

This inequality tells us that the score in the third quiz must be larger than or equal to 72.
Now we study the second inequality to find the other restriction on "x":

This ine
quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.
Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:
So there's 8 tiles.
Radius from archway to the outer edge would be : 7 +1 = 8ft
You can use this formula to count the area of semi circle : π r^2/2
A = 3.14 x 8ft^2 = 100.48 ft ^2
A = 3.14 x 7ft^2= 76.92 ft^2
100.48 - 76.92 = 23.55 ft^2
Then you have to divide it with the total tiles
23.55/8 = 2.94 ft^2 per tile >> (rounded to nearest tenth)
hope this helps
As a = 0 , there is no sign . Its only 0. Thus the answer is (c)
Answer:
44.1 x 10^-2
Step-by-step explanation:
Since one grain
= 7 x 10^-5
6300kg = 7 x 10^-5 x 6300
Put 6300 in standard form
7 x 10^-5 x 6.3 x 10^3
Multiply the whole numbers and add the exponents
7 x 6.3 x 10^-5 + 3
44.1 x 10^-2
There are 44.1 x 10^-2 grains of sand in 6300kg