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Nutka1998 [239]
3 years ago
14

What’s my line point

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

Step-by-step explanation:

6 -3

grandymaker [24]3 years ago
7 0

Answer:

[In Picture]

y=-\frac{3}{4}x-2

The line would go past -2, since that is the y-intercept.

The slope of the graphed line would be -3/4

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Eddi Din [679]
The answer is 48 degrees because you add 42 and 90 and then subtract from 180 (total degrees of a triangle)
8 0
2 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
What is 75.4 in expanded form
Shalnov [3]

Answer: 75.4 =

 70  

+ 5  

+   0.4

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
Write the first 4 terms in the sequence defined by the explicit rule f(n)=n^2 - 5 *n^2 means n squared
Deffense [45]
The question did not spesify the stating value for n.

Assuming, n = 0 is the starting value.

1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5

2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4

3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1

4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4

Therefore, the first 4 terms are: -5, -4, -1, 4.
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3 years ago
If there are 6 people, and each person has 2 coins, there are __ times as many coins as people.​
never [62]

Answer:

2

Step-by-step explanation:

6x2=12 12/6=2

3 0
2 years ago
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