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Schach [20]
3 years ago
9

138 = n + 38A() 100B() 200C() 250D() 150

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0
It is definetely A()100
Keith_Richards [23]3 years ago
3 0
Your answer is A ! You have to try and get your “n” variable by itself so you cancel out the 38. You subtract 38 from itself and from the 138. Your answer will be n = 130.
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Let X be the number of purchases that Fred will make on the online site for a certain company (in some specified time period). S
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Answer: ???

Step-by-step explanation:

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3 years ago
Someone please help me
Inessa05 [86]

9514 1404 393

Answer:

  A.  16°

Step-by-step explanation:

Angle E corresponds to angle N, the third angle in ∆MNO. Its measure is ...

  ∠N = 180° -∠M -∠O

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6 0
2 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

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Anon25 [30]

We have a function,

f(x)=x^2-1

and we are asked to find its inverse function.

An inverse function essentially gets you the original value that was dropped into a function.

For example,

If I put 5 into f(x) I will get 24. Now If I take 24 and put it into the inverse function I have to get number 5 back.

The way to determine the inverse function swap the x and the f(x), then solve for f(x),

x=f(x)^2-1

f(x)^2=x+1

f(x)=\pm\sqrt{x+1}

Of course the notation demands that the obtained function be called,

f^{-1}(x)=\pm\sqrt{x+1}

Hope this helps :)

6 0
2 years ago
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