35
the ratio for the two is 5:7 and you want to find _:49. to get from 7 to 49 you multiply the 7 by 7. because you did that to one side you have to do the same to the other and multiply 5 by 7 which gives you 35
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer: -$6,500
Step-by-step explanation:
Here we could , use the arithmetic progression where
T(2020 - 2010) = a + ( n - 1 )d
T10 = a + ( 10 - 1 )d --------------- 1
a = $25,000, n = 10 and d = 14% of $25,000 = $3,500 the common difference.
Note since it decreases the common difference d = -$3,500.
Now substitute for the values in the equation above.
T10 = 25,000 + 9 x -3,500
= $25,000 - $31,500
= -$6,500 (deficit )
Answer:
yeah. in this case and shape it's rather obvious.
but furthermore the sum of all angles are 360°!
(numberOfAngles * 180 - 360)