Proof: We know that angle CBA is congruent to angle FBA and
that angle CAB is congruent to angle FAB because the corresponding angles have the
same measure in degrees (as evidenced in the given equation). We see that angle
BCA is congruent to angle BFA by the reflexive property of congruence (More
accurately Third Angle Theorem). Therefore, we can conclude that triangle BCA
is congruent to triangle BFA because a pair of corresponding angles and the included side are equal, since the two triangles share a line segment (AB).
Solve for x and y? Nsjsjd
Based in the given figure, we are being asked to solve the area and the perimeter of the semicircle. As we evaluate the problem, we can get a radius measurement from the rectangle. Hence, the radius is half of 4 inches which is 2 inches and since we know the formula for solving the area of a circle which is Area = pi*r², dividing the result by two, we able to get the area of the half of a circle which is equivalent to the area of the semicircle.
Area of circle = pi*r²
Area of circle = 3.14*(2)² = 12.56
Therefore, area of semicircle is = (1/2) 12.56
Area of semicircle = 6.28 inches²
Solving for the perimeter:
Semicircle Perimeter = 1/2 * pi* d+d where d is the diameter (diameter = 4 inches)
Semicircle Perimeter = 1/2 * 3.14*4+4
Semicircle Perimeter = 10.28 inches
Answer:
two cubes one 24 m per side one 7m per side
Step-by-step explanation:
24 x 6 = 144 + 7 times 6 = 186
vs
25 times 6 = 150
The answer will be 29cm²
Hope This Helps and God Bless!
