Answer:
The arc measure of ∠ADE is equal to 333 degrees.
Step-by-step explanation:
Please refer to the attached diagram,
Let the unknown angle ∠APE = x
Since BD is the diameter of the circle then
∠APE + ∠DPE + ∠APB = 180°
∠APE + 63° + 90° = 180°
x + 63° + 90° = 180°
Solving for x
x = 180° - 90° - 63°
x = 90° - 63°
x = 27°
Since a circle has 360° then
∠ADE + ∠APE = 360°
∠ADE + x = 360°
∠ADE + 27° = 360°
∠ADE = 360° - 27°
∠ADE = 333°
Therefore, the arc measure of ∠ADE is equal to 333 degrees.
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.
We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)
N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA
D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA
Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A
This verifies the identity.
Answer:
3, 6, 4, 5
Step-by-step explanation:
First of all we have to multiply 2 by 2x and -9 and we obtain
4x -18 ≤ 6
now we have to move -18 on the right side of the minor or equal and change its sign
4x ≤ 6 + 18
now we have to added up 6 and 18
4x ≤ 24
At least we have to divide the the two members by 4
x ≤ 6
We have to find the numbers ≤ 6
so the answer is : 3, 6, 4, 5
0.8 and 0.80 are named the same because both of them numbers have an 8 in the tenths place and a zero in the hundredths place. No matter how many zeros you add on to the end of the decimal, it does not change its value.
