Let
x-------------> pounds of granola-----------> <span>$3 per pound
</span>y-------------> pounds of raisins-----------> $2 per pound
z------------ > price per <span>pounds of the trail mix
</span>
we have that
z=3x+2y--------------------- > this is the equation
for x=3 pounds of granola and y=<span>0.75 pounds of raisins
z=3*3+2*0.75=</span>$10.5 of <span>trail mix</span>
Answer:
a) To increase 160 by 4% we multiply by 1.04
b) To decrease 160 by 6% we multiply by 0.94
Step-by-step explanation:
a) Here we have to increase 160 by 4% we are to note that;

Therefore, increasing 160 by 4% is to add additional 0.04×160 to 160
That is 160 + 0.04×160 = 160×(1 + 0.04) = 160×1.04
Therefore Sue should have multiplied 160 by 1.04 to increase 160 by 4%.
b) Here to decrease 160 by 6%, we subtract 6% of 160 from 160 that is;
Decrease 160 by 6% = 160 - 160×0.06 = 160×(1 - 0.06) = 160 × 0.94 = 150.4
Hence to decrease 160 by 6% we multiply by 0.94.
Using the z-distribution, it is found that the needed sample sizes are:
a) 242
b) 1842
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which z is the z-score that has a p-value of
.
The margin of error is:

99% confidence level, hence
, z is the value of Z that has a p-value of
, so
.
Item a:
The estimate is:

The sample size is <u>n for which M = 0.03</u>, then:






Rounding up, a sample of 242 is needed.
Item b:
No prior estimates, hence
is used.






Rounding up, a sample of 1842 is needed.
For more on the z-distribution, you can check brainly.com/question/25404151
C1000÷ct=w
you pretty much ×1000 and then ÷t and c