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ololo11 [35]
3 years ago
10

I need help please . It's factoring

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0
I figured it out in a word doc. See attachment.
Download docx
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Answer: Yes, the answers in the blanks are correct.

Step-by-step explanation: The easiest way to answer this question is to plot the points onto a graph. The point (0,10) is right on the y-axis, so that would be the y-intercept. The best way to find the slope is the rise over run method. The slope 2/5 is correct because it "rises" by 2 units and "runs" by 5 units.

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3 years ago
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A hose is leaking water at a rate of 2 oz/h. How many cups of water will leak out after 2 weeks?
Over [174]

Answer:

84 cups of water will leak out after 2 weeks

Step-by-step explanation:

* Lets how many how to change oz to cup

- One cup contains 8 oz

- We can use the ratio to solve this problem

- A hose is leaking water at a rate of 2 oz/h

- We need to find how many cups of water will leak out after 2 weeks

∵ The rate of the water leak out is 2 oz/hr

∵ 1 cup contains 8 oz

∴ 1 oz = \frac{1}{8} cup

∴ 2 oz = 2 × \frac{1}{8} = \frac{2}{8} = \frac{1}{4} cup

∴ The rate of the water leak out = \frac{1}{4} cup/h

∵ 1 day = 24 hours

∵ 1 week = 7 days

∴ 1 week = 7 × 24 = 168 hours

∵ The number of hours in 1 week is 168

∴ The number of hours in 2 weeks = 168 × 2 = 336 hours

⇒    cups    :    hours

⇒      \frac{1}{4}         :   1

⇒     x         :    336

- By using cross multiplication

∴ x = 336 × \frac{1}{4}

∴ x = 84

- x represents the number of cups of water leak out

<em>84 cups of water will leak out after 2 weeks</em>

5 0
4 years ago
If the probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more cars on any given workday are, respect
Readme [11.4K]

Answer:

P(X\geq 5)=0.69

Step-by-step explanation:

We need to find the probability that the mechanic will service  or more cars.

It's a simpler one given that we have the probabilities of servicing 4 or less cars.

P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.

P(X\geq 5)=1-p(x=4)-p(x=3)\\P(X\geq5)=1-0.12-0.19\\P(X\geq5)=1-0.31\\=0.69

5 0
3 years ago
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