Which quadratic equation fits the data in the table? x -5,-2,-1,0,3,4,6 y 33,9,5,3,9,15,33
mojhsa [17]
Answer:
y = x² − x + 3
Step-by-step explanation:
Quadratic equation is:
y = ax² + bx + c
Pick three points and plug in. I'll choose (-2, 9), (-1, 5), and (0, 3).
9 = a(-2)² + b(-2) + c
5 = a(-1)² + b(-1) + c
3 = a(0)² + b(0) + c
9 = 4a − 2b + c
5 = a − b + c
3 = c
We know c = 3, so substitute into the first two equations:
9 = 4a − 2b + 3
5 = a − b + 3
0 = 4a − 2b − 6
0 = a − b − 2
Solve by elimination or substitution.
b = a − 2
0 = 4a − 2(a − 2) − 6
0 = 4a − 2a + 4 − 6
0 = 2a − 2
a = 1
b = -1
Therefore:
y = x² − x + 3
Answer:
y=2^x
Step-by-step explanation:
675/1000. Simplified it would be 27/40.
Using probability concepts, it is found that P(S and D) = 0.1275.
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- A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
- In a standard deck, there are 52 cards.
- Of those, 13 are spades, and 13 are diamond.
- The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

Thus, P(S and D) = 0.1275.
A similar problem is given at brainly.com/question/12873219