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Kryger [21]
3 years ago
9

Evaluate 7-\left(-19\right)-18+\left(-19\right)+187−(−19)−18+(−19)+187, minus, left parenthesis, minus, 19, right parenthesis, m

inus, 18, plus, left parenthesis, minus, 19, right parenthesis, plus, 18.
Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0

Answer:

345

Step-by-step explanation:

7-\left(-19\right)-18+\left(-19\right)+187-\left(-19\right)-18+\left(-19\right)+187

7+19-18+\left(-19\right)+187-\left(-19\right)-18+\left(-19\right)+187

26-18+\left(-19\right)+187-\left(-19\right)-18+\left(-19\right)+187

8+\left(-19\right)+187-\left(-19\right)-18+\left(-19\right)+187

8-19+187-\left(-19\right)-18+\left(-19\right)+187

-11+187-\left(-19\right)-18+\left(-19\right)+187

176-\left(-19\right)-18+\left(-19\right)+187

195-18+\left(-19\right)+187

177+\left(-19\right)+187

177-19+187

158+187

=345

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3 0
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Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence inte
Georgia [21]

Answer:

The  90%  confidence interval for population mean is   14.7  <  \mu  <  19.1

Step-by-step explanation:

From the question we are told that

   The sample mean is  \= x  =  16.9

    The confidence level is  C  =  0.90

     The sample size is  n  =  45

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       \alpha =  1-0.90

       \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2}  from the standardized normal distribution table. The values is  Z_{\frac{\alpha }{2} } =  1.645

The  reason we are obtaining critical values for \frac{\alpha }{2}  instead of  that of  \alpha  is because \alpha  represents the area under the normal curve where the confidence level 1 - \alpha (90%)  did not cover which include both the left and right tail while \frac{\alpha }{2}  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

         MOE  = 1.645*  \frac{ 9 }{\sqrt{45} }

         MOE  = 2.207

The  90%  confidence level interval is mathematically represented as

      \= x  -  MOE  <  \mu  <  \= x  +  MOE

substituting values

     16.9 -  2.207  <  \mu  <  16.9 +  2.207

    16.9 -  2.207  <  \mu  <  16.9 +  2.207

     14.7  <  \mu  <  19.1

         

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3 years ago
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