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Rzqust [24]
3 years ago
15

Which graph shows the solution to the equation below? log Subscript 3 Baseline (x + 3) = log Subscript 0.3 (x minus 1)

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:

The answer is 20

Step-by-step explanation:

(Edge2020)

AleksandrR [38]3 years ago
4 0

Answer:

Its A on edge

Step-by-step explanation:

i took the test. good luck guys!

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What number is 9/21 of 1260?
devlian [24]

Answer:

It's 540.

Step-by-step explanation:

You divide 9 by 21 then you multiply it by 1260 and you get 540

3 0
3 years ago
Find all the powers of 4 in the range 4-1000
lara31 [8.8K]

4¹ =  4
4² =  16
4³ =  64
4⁴ =  256

(4⁵ =  1,024  too big)

3 0
3 years ago
Who ever answers gets points
MAXImum [283]

Hello! How are you today?

6 0
2 years ago
What is the compliment of a 62° angle.
krok68 [10]

Answer:

28°

Step-by-step explanation:

complimentary angles = their sum is 90.

so to find the complimentary angle of 62, just subtract it from 90.

90-62 = 28

your answer is 28°

good luck with your schoolwork/homework!

---------------------------------------------------------------------

apologies in advance for incorrect answers or bad explanations.

3 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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