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Aloiza [94]
3 years ago
14

A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimat

es that each tree will yield 300 board-feet. Estimate the yield of the stand if one-tenth of the trees are cut. ​
Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

Step-by-step explanation:

First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)

n = \sigma \cdot A

Where:

\sigma - Surface density, measured in trees per square meter.

A - Total area, measured in square meters.

Given that \sigma = \frac{1}{20}\,\frac{tree}{m^{2}} and A = 24\,h, the total amount of fir trees is:

n = \left(\frac{1}{20}\,\frac{trees}{m^{2}}  \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)

n = 12000\,trees

It is known that one-tenth of the tress are cut, whose amount is:

n_{c} = 0.1 \cdot n

n_{c} = 0.1 \cdot (12000\,trees)

n_{c} = 1200\,trees

If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:

y = S\cdot n_{c}

Where:

S - Yield of the tress, measured in board-feet per tree.

n_{c} - Amount of trees that will be cut, measured in trees.

If n_{c} = 1200\,trees and S = 300\,\frac{b-ft}{tree}, then:

y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)

y = 360000\,b-ft

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

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for competition,the cheerleading team,is preparing a dance routine that must last 4 minutes,with a variation of +- 5 seconds. fi
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Ideal timeline of the dance routine = 4 minutes = 4 × 60 seconds = 240 seconds

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3 0
3 years ago
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Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) :x^2+y^2+4z^2=36

Parametric equations:

x=-4t-1

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Finding the gradient of function

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